Real Projective Space

We define an equivalence relation on Rn+1∖{0} by $$x \sim y \iff \exists t \in \Bbb R(y = tx)$$where x,y∈Rn+1∖{0}. The real projective space RPn or Pn(R) is the quotient space of Rn+1∖{0} by this equivalence relation. We denote the equivalence class of a point (a0,…,an)∈Rn+1∖{0} by [a0,…,an] and let π:Rn+1∖{0}→RPn be the projection. We call [a0,…,an] homogeneous coordinates on RPn.

Geometrically, two nonzero points in Rn+1 are equivalent iff thy line in the same line through the origin, so RPn can be interpreted as the set of all lines through the origin in Rn+1. Each line through the origin in Rn+1 meets the unit sphere Sn in a pair of antipodal points, and conversely, a pair of antipodal points on Sn determines a unique line through the origin. This suggest that we can define an equivalence relation ∼ on Sn by identifying antipodal points: $$x\sim y \iff x = \pm y, \qquad x, y\in \Bbb S^n$$We have the bijection RPn↔Sn/∼.

Then we have that RPn is compact.

Prop: The equivalence relation ∼ on Rn+1∖{0} in the definition of RPn is an open equivalence relation. This can be seen as the Continuous Actions of Groups (scalar multiplication) on the topological space Rn+1∖{0}.

Cor: The real projective space RPn is second countable

Prop: The real projective space RPn is T2.

The Standard Smooth Atlas on a Real Projective Space

Let [a0,…,an] be homogeneous coordinates on the projective space RPn. a0 is not a well-defined function RPn, the condition a0≠0 is independent of the choice of representative for [a0,…,an]. With this condition, we can define: $$U_0 := {[a^0, \dots, a^n]\in \Bbb {RP}^n \mid a^0\neq 0}$$Similarly, for each i∈{1,…,n}, let $$U_i := {[a^0, \dots, a^n]\in \Bbb {RP}^n \mid a^i \neq 0}$$
We define the map: ϕi:Ui→Rn by $$[a^0, \dots, a^n] \mapsto \left(\frac{a^0}{a^i}, \dots, \hat{\frac{a^i}{a^i}}, \dots \frac{a^n}{a^i}\right)$$where the caret sign ^ over ai/ai means that entry is to be omitted. This proves that RPn is locally Euclidean with the charts (Ui,ϕi) as charts.

Meaning that RPn is a topological manifold of dimension n.

It is easy to show that {(Ui,ϕi)∣i∈{0,…,n}} is a C∞ atlas for RPn, called the standard atlas. Meaning that RPn is a smooth manifold.

As CW Complex

If we consider the the usual inclusion Rk+1⊆Rn+1 for k<n, this allows us to consider RPk as a subspace of RPn. Then RPn has a CW decomposition with one cell in each dimension 0,…,n such that the k-skeleton is RPk for 0<k<n.

As Quotient of a Zero Dimensional Lie Group

The two-element group {±1} acts on Sn by multiplication. This action is obviously smooth and free, and it is proper because the group is compact. This defines a smooth structure on Sn/{±1}. In fact, this quotient manifold is diffeomorphic to RPn with smooth structure we defined above. Let p:Sn→RPn be the smooth covering map obtained by restricting the canonical projection Rn+1∖{0}→RPn to the sphere. This map makes the same identification as the quotient map π:Sn→Sn/{±1}. This Sn/{±1} is diffeomorphic to RPn, and RPn is a compact manifold.

Real Projective Varieties

On the projective space RPn a homogeneous polynomial F(x0,…,xn) of degree k is not a function, since its value at a point [a0,…,an] is not unique. However, the zero set in RPn of a homogeneous polynomial F(x0,…,xn) is well defined, since F(a0,…,an)=0 if $$F(ta_0, \dots, ta_n) = t^kF(a_0, \dots, a_n) = 0, \qquad \forall t\in \Bbb R ^\times$$The zero set of finitely many homogeneous polynomials in % is called a real projective variety. A projective variety defined by a single homogeneous polynomial of degree k is called a hypersurface of degree k.

Covering Spaces

Since p:Sn→RPn be the smooth covering map by restricting the canonical projection Rn+1∖{0}→RPn to the sphere. We see that Sn to be the universal covering space for RPn for n≥2. In the case of n=1, we know that S1≅RP1, which has a universal covering space of R.

For n≥1, consider the smooth covering map q:Sn→RPn. The only nontrivial covering automorphism of q is the antipodal map α(x):=−x. We see that α is orientation-preserving iff n is odd, so it follows that RPn is orientable iff n is odd.