Line Integral over a Vector Field

Subjects: Vector Analysis
Links: Rectifiable Curves in Rn, Riemann Integral in R, Vector Valued Functions of Rn

Def: Let URn be an open an connected set, a curve ΓU and γ:[a,b]Rn be a piecewise smooth function such that Γ=γ[[a,ba,b]], and the function F=(Fk)k=1n:URn a function such that for any Fkγ be integrable over [a,b] for any k{1,,n}. We define the integral of F over the curve Γ with the parametrization γ as

ΓFdr=ΓFdγ=abF(γ(t))γ(t)dt

Where dr is representing the differential of position, in a weireder notation we get that

ΓFdr=Γk=1nFidxi

If the curve is closed it can be denoted as follows, but it doesn’t change the nature of the calculation:

Γfdγ=Γfdr

Prop:* Let URn be a open and connected set, and ΓU be piecewise smooth and γ:[a,b]Rn be a piecewise smooth parametrization of Γ. Let F,G:URn be such that Fkγ and Gkγ be integrable over [a,b] for any k{1,,n}, and α,βR, then

Γ(αF+βG)dγ=αΓFdγ+βΓGdγ

Prop:************ Let URn be a open and connected set, and Γ,ΔU and piecewise smooth curves parametrized by γ:[a,b]Rn and δ:[c,d]Rn respectively, such that ΓΔ be piecewise smooth parametrized by γδ . If F:UR is such that Fkγ and Fkδ be integrable over their respective intervals for any k{1,,n} then

ΓΔfd(γδ)=Γfdγ+Δfdδ

Cor:************ Let ΓRn be a piecewise smooth nonsimple curve with a finite number of intersections parametrized by γ:[a,b]Rn, then we can split γ into γ1,,γk simple curves such that γ=γ1γk

Γfdγ=i=1kΓifdγi

Prop:************ Let URn be a open and connected set, and ΓU be piecewise smooth and γ:[a,b]Rn and δ:[c,d]Rn be piecewise smooth parametrizations of Γ, and F:URn be such that Fkγ and Fkδ be integrable for in their respective intervals for any k{1,,n}. If there’s and α:[c,d][a,b] be a C1 bijection with the property that δ=γα, then