3D Wave Equation

Subjects: Fourier Analysis, Partial Differential Equations
Links: The Wave equation, Fourier Transform in Rn, Scalar Surface Integral

If S2 denotes the unit sphere in R3, we define the spherical mean of f over the sphere of radius t centred at x by $$M_t(f)(x) = \frac{1}{4\pi} \int_{\Bbb S^2} f(x-t\gamma), d\sigma(\gamma)$$where dσ(γ) is the element of surface area for S2. Since 4π is the area of the unit sphere, we can interpret Mt(f) as the average value of f over the sphere centred at x with radius t

We can also write this in another form $$M_t(f)(x) ) \frac1{|S(x,t)|} \int_{S(x, t)} f(\gamma),d\sigma(\gamma)$$where S(x,t) denotes the sphere of centre x and radius t and |S(x,t) its area.

Lemma: If fS(R3) and t is fixed, then Mt(f)S(R3). Moreover Mt(f) is infinitely differentiable in t, and each t-derivative also belongs to S(R3)

Lemma: $$\frac1{4\pi} \int_{\Bbb S^2} e^{-2\pi i \omega\cdot \gamma}, d\sigma(\gamma) = \frac{\sin(2\pi|\omega|)}{2\pi|\omega|}$$
By the defining formula for the spherical mean, we may interpret Mt(f) as a convolution of the function f with the element dσ, and since the Fourier transform interchanges convolutions with products, we are lead to believe that Mt(f)^ is the product of the corresponding Fourier transforms. $$\widehat{M_t(f)}(\omega) = \hat f(\omega) \frac{\sin(2\pi |\omega| t)}{2\pi |\omega| t}$$
Th: The solution when n=3 of the Cauchy problem wave equation $$\Delta u = \frac{\partial^2 u}{\partial t^2} \quad \text{subject to} \quad u(x, 0) = f(x) \quad \text{and}\quad \frac{\partial u}{\partial t} (x, 0)=g(x)$$
is given by $$u(x,t) = \frac{\partial}{\partial t}(t M_t(f)(x)) + t M_t(g)(x)$$
We can get another way to solve to write the solution, using the other way to write the spherical mean of f, getting $$u(x, t) = \frac1{|S(x,t)}\int_{S(x,t)} [tg(y)+f(y)+ \nabla f(y) \cdot (y-x)], d\sigma(y)$$
This alternate expression for the solution of the wave equation is sometimes called Kirckchoff's formula