If denotes the unit sphere in , we define the spherical mean of over the sphere of radius centred at by $$M_t(f)(x) = \frac{1}{4\pi} \int_{\Bbb S^2} f(x-t\gamma), d\sigma(\gamma)$$where is the element of surface area for . Since is the area of the unit sphere, we can interpret as the average value of over the sphere centred at with radius
We can also write this in another form $$M_t(f)(x) ) \frac1{|S(x,t)|} \int_{S(x, t)} f(\gamma),d\sigma(\gamma)$$where denotes the sphere of centre and radius and its area.
Lemma: If and is fixed, then . Moreover is infinitely differentiable in , and each -derivative also belongs to
Lemma: $$\frac1{4\pi} \int_{\Bbb S^2} e^{-2\pi i \omega\cdot \gamma}, d\sigma(\gamma) = \frac{\sin(2\pi|\omega|)}{2\pi|\omega|}$$
By the defining formula for the spherical mean, we may interpret as a convolution of the function with the element , and since the Fourier transform interchanges convolutions with products, we are lead to believe that is the product of the corresponding Fourier transforms. $$\widehat{M_t(f)}(\omega) = \hat f(\omega) \frac{\sin(2\pi |\omega| t)}{2\pi |\omega| t}$$ Th: The solution when of the Cauchy problem wave equation $$\Delta u = \frac{\partial^2 u}{\partial t^2} \quad \text{subject to} \quad u(x, 0) = f(x) \quad \text{and}\quad \frac{\partial u}{\partial t} (x, 0)=g(x)$$
is given by $$u(x,t) = \frac{\partial}{\partial t}(t M_t(f)(x)) + t M_t(g)(x)$$
We can get another way to solve to write the solution, using the other way to write the spherical mean of , getting $$u(x, t) = \frac1{|S(x,t)}\int_{S(x,t)} [tg(y)+f(y)+ \nabla f(y) \cdot (y-x)], d\sigma(y)$$
This alternate expression for the solution of the wave equation is sometimes called Kirckchoff's formula